We have, (8√5+6√2)100
Here, Tr+1= 100Cr(8√5)100−r(6√2)r
= 100Cr(5)100−r8(2)r6
Thus, for Tr+1 to be rational
(1) 100−r should be a multiple of 8, and
(2) r should be a multiple of 6
So possible values of r (0≤r≤100) for terms to be rational are {12,36,60,84}
∴ number of irrational terms = total terms − number of rational terms = 101−4=97