The number of irrational terms in the expansion of (8√5+6√2)100 is
A
97
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B
98
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C
96
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D
99
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Solution
The correct option is B97 Tr+1=100Cr5(100−r8)2(r6) For rational terms, 100−r should be a multiple of 8 and r should be a multiple of 6
Hence we get rational terms for r=12,36,60 and 84 Hence there will be 4 rational terms. Therefore, total number of irrational terms will be 101−4 =97 terms.