The number of isomers (excluding geometrical and stereoisomers) for (A) is:

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Solution

DBU of the given compound comes out to be 5. From the reaction given, it can be seen that the benzene ring (DBU = 4) is present in the starting compound and $B r_{2} / C C l_{4}$ addition is not happening means the possibilities of double bond and triple bond are eliminated. Hence the starting compound has some cyclic part (DBU = 1) attached with benzene.
Hence the following are the possible isomers:

Since (V) will not produce phthalic acid upon oxidation. So a total of 5 isomers are possible.

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