The number of isomers for the compound with molecular formula $C_{2} B r C l F l$ is:
(A) 3 (B) 4
(C) 5 (D) 6

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Solution

The correct answer is D

6 isomers will be possible for this formula.
Take two halogens on one of the double bonded carbon and you will have three possible combinations.
For each of these three structures, there will be CIS and Trans Structure and total 6

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The number of isomers for the compound with molecular formula C2BrClFl is:(A) 3 (B) 4(C) 5 (D) 6

The correct answer is D6 isomers will be possible for this formula. Take two halogens on one of the double bonded carbon and you will have three possible combinations. For each of these three structures, there will be CIS and Trans Structure and total 6

The number of isomers for the compound with molecular formula $C_{2} B r C l F l$ is:
(A) 3 (B) 4
(C) 5 (D) 6

The correct answer is D

6 isomers will be possible for this formula. Take two halogens on one of the double bonded carbon and you will have three possible combinations. For each of these three structures, there will be CIS and Trans Structure and total 6