The number of isomers possible for disubstituted borazine, $B_{3} N_{3} H_{4} X_{2}$ is:

3

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4

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6

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5

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Solution

The correct option is B $4$
The number of isomers possible for disubstituted borazine, $B_{3} N_{3} H_{4} X_{2}$ is $4$

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