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Byju's Answer
Standard XII
Mathematics
Parametric Form of Tangent: Ellipse
The number of...
Question
The number of limiting points of orthogonal coaxial system of the coaxial system
x
2
+
y
2
+
2
λ
x
−
5
=
0
are
A
0
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B
1
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C
2
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D
4
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Solution
The correct option is
B
2
x
2
+
y
2
+
2
λ
x
−
5
=
0
radius
=
√
λ
2
+
5
>
0
So, there are two limiting points exists.
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0
Similar questions
Q.
lf
(
1
,
2
)
and
(
3
,
4
)
are limiting points of the given coaxial system then the least circle belonging to the orthogonal coaxial system is
x
2
+
y
2
+
a
x
+
b
y
+
c
=
0
. Then
(
a
,
c
)
=
Q.
The number of real circles belonging to the coaxial system
x
2
+
y
2
+
2
λ
x
+
c
=
0
(
λ
is a variable) and whose centre lie between the limiting points of the given coaxial system is
Q.
The equation of the common radical axis of the orthogonal coaxial system of the coaxial system
(
x
2
+
y
2
−
4
x
−
6
y
+
5
)
+
λ
(
2
x
+
3
y
+
4
)
=
0
is
Q.
i) The coaxial system
x
2
+
y
2
+
2
λ
x
+
5
=
0
is a non intersecting system.
ii) The coaxial system
x
2
+
y
2
+
4
λ
x
−
3
=
0
is an intersecting system.
Which of the above statements is(are) correct?
Q.
The limiting points of the system of coaxial circles
x
2
+
y
2
+
2
f
y
+
25
=
0
are
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