Question

The number of lone pairs of electron on $Xe$ in $XeO{F}_4$ is:

• A. $1$
• B. $2$
• C. $3$
• D. $4$

Answer 1

Answer: (A)

$1$

The number of lone pairs of electron on $Xe$ in $XeO{F}_4$ is 1. $Xe$ in $XeO{F}_4$ has ${sp}^3{d}^2$-hybridization having one lone pair on $Xe$-atom and is square pyramidal in shape.