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Question

The number of minterms after minimizing the following Boolean expression [D+AB+AC+ACD+ACD]
is _____

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Solution

[D+AB+AC+ACD+ACD]

=[D+ACD+AB+AC+ACD]
=[D+AC+AB+A[C+CD]]
=[D+AC+AB+A[C+D]]
=[D+AC+AB+AC+AD]
(D+AD=D+A)
=[D+A+AC+AB+AC]
A+AC+=A
A+AC+AB=A+A(C+B)=A+C+B
=[D+A+C+B]
=ABCD
Hence, only 1 minterm is required.

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