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Ion Electron Method

The number of...

Question

The number of mole of Mohr's salt required for reduction of one mole of $K_{2} C r_{2} O_{7}$ is :

A

3

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B

4

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C

5

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D

6

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Solution

The correct option is D 6
In Mohr's salt, only $F e S O_{4}$ reacts with $K_{2} C r_{2} O_{7}$ according to the following equation:
$K_{2} C r_{2} O_{7} + 6 F e S O_{4} \to 6 F e^{+ 3} + 2 C r^{+ 3}$
So, for one mole of $K_{2} C r_{2} O_{7}$ , 6 moles of Mohr's salt is required.

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