Question

The number of molecules in 100 ml of 0.02 N $H_{2}S{O}_4$ is

• A. $6.02\times {10}^{22}$
• B. $6.02\times {10}^{21}$
• C. $6.02\times {10}^{20}$
• D. $6.02\times {10}^{18}$

Answer 1

The correct option is C $6.02\times {10}^{20}$

$0.02N{H}_{2}S{O}_4=0.01M{H}_{2}S{O}_4$
$H_{2}S{O}_4=0.01Mole$
$\therefore$ 100 ml of 0.01 M $H_{2}S{O}_4$ contains $H_{2}S{O}_4$
$=0.001mole={10}^{-3}mole$
$\therefore$ Molecules present $={10}^{-3}\times 6.02\times {10}^{23}$
$=6.02\times {10}^{20}$