Question

The number of molecules in 22.4 $c{m}^3$ of nitrogen gas at STP is __________.

• A. $6.023\times {10}^{20}$
• B. $6.023\times {10}^{23}$
• C. $22.4\times {10}^{20}$
• D. $22.4\times {10}^{23}$

Answer 1

The correct option is A $6.023\times {10}^{20}$

There are 6.022*10^23 molecules present in 22400cm^3 gas.
Therefore the no. of molecules present in 22.4cm^3=
6.022*10^23 * 22.4cm^3 divide by:
224000 cm^3
Hence we get the ans as 6.022*10^20 molecules.