THe number of molecules in 4-25 g of ammonia is- a 1-0 - 1023 b 1-5 - 1023 c 2-0 - 1023 d 3-5 - 1023

Molar mass NH_3 = 14+3 = 17g/mol No of moles in 4.25g = 4.25/17 = 0.25 mol 1mol = 6.022 molecules 0.25 mol = 0.256.022 Number of molecules = 1.51 molecules NH ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Chemistry

Mole Concept and Avogadro's Number

THe number of...

Question

THe number of molecules in 4.25 g of ammonia is:
(a) $1.0 \times 10^{23}$ (b) $1.5 \times 10^{23}$
(c) $2.0 \times 10^{23}$ (d) $3.5 \times 10^{23}$

Open in App

Solution

Molar mass $N H_{3}$ = 14+3 = 17g/mol
No of moles in 4.25g $= \frac{4.25}{17} = 0.25 m o l$
1mol = 6.022 molecules
0.25 mol = 0.256.022
Number of molecules = 1.51 molecules $N H_{3}$

Option b is correct

Suggest Corrections

Similar questions

The number of molecules in 4.25 g of ammonia is approximately

The number of molecules present in $4.25 g r a m s$ of $N H_{3}$ is approximately:

Q. The number of atoms present in 4.25 grams of NH3 is approximately:

The number of atoms present in $4.25 g r a m s$ of $N H_{3}$ is pproximately

Find the number of H atoms in $9.033 \times 10^{23}$ molecules of water.

Join BYJU'S Learning Program

THe number of molecules in 4.25 g of ammonia is: (a) 1.0×1023 (b) 1.5×1023 (c) 2.0×1023 (d) 3.5×1023

Molar mass NH3 = 14+3 = 17g/mol No of moles in 4.25g =4.2517=0.25mol 1mol = 6.022 molecules 0.25 mol = 0.256.022 Number of molecules = 1.51 molecules NH3 Option b is correct

THe number of molecules in 4.25 g of ammonia is:
(a) $1.0 \times 10^{23}$ (b) $1.5 \times 10^{23}$
(c) $2.0 \times 10^{23}$ (d) $3.5 \times 10^{23}$

Molar mass $N H_{3}$ = 14+3 = 17g/mol
No of moles in 4.25g $= \frac{4.25}{17} = 0.25 m o l$
1mol = 6.022 molecules
0.25 mol = 0.256.022
Number of molecules = 1.51 molecules $N H_{3}$

Option b is correct