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Stoichiometric Relation

The number of...

Question

The number of molecules of $C O_{2}$ present in 44g of $C O_{2}$ is:

6.0 \times 10^{23}

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3 \times 10^{23}

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12 \times 10^{23}

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3 \times 10^{10}

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Solution

The correct option is C $6.0 \times 10^{23}$
Molecular mass in gms $= 6.02 \times 10^{23}$ molecules.
Molecular mass of $C O_{2} = 12 + 16 + 6 = 44$ gms.
$∴$ 44g of $C O_{2}$ has $6.0 \times 10^{23}$ molecules of $C O_{2}$

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