The number of moles of a gas in $1 m^{3}$ of volume at NTP is:

4.46

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0.446

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1.464

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44.6

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Solution

The correct option is D 44.6
22.4 L contains 1 mole of gas
Therefore, no. of moles in 1m $^{3}$ or 10 $^{3}$ L = $\frac{1}{22.4} \times 10^{3}$
=44.6

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The number of moles of a gas in 1 $m^{3}$ of volume at N.T.P. is

1 m^{3}

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