Question

The number of moles of a gas in 1$m^3$ of volume at NTP is:-

• A. 4.46
• B. 0.446
• C. 1.464
• D. 44.6

Answer 1

The correct option is D 44.6

22.4 liter of any gas $=$ 1 mole of that gas

1 liter $=1d{m}^3$ and 1m$=$10dm

So,1dm$=\frac{1}{10}m$

1L$=1{\left(\frac{1}{10}m\right)}^3$

$1{\left(\frac{1}{10}m\right)}^{3}1L=\frac{1m^3}{1000}1L={10}^{-3}{m}^{3}so,22.4L=22.4\times {10}^{-3}{m}^{3}Hence22.4\times {10}^{-3}{m}^{3}Have=1mole1m^{3}Have=\frac{1}{22.4\times {10}^{-3}}mole=\frac{1000}{22.4}=44.6mole$