The number of moles of acidified $K M n O_{4}$ required to convert sulphite ion into sulphate ion is:

2/5

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3/5

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4/5

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Solution

The correct option is A 2/5
$2 K M n O_{4} + 5 H_{2} S O_{3} \to K_{2} S O_{4} + 2 M n S O_{4} + 2 H_{2} S O_{4} + 3 H_{2} O$

2/5 moles of acidified $K M n O_{4}$ will convert sulphite ion into sulphate ion.

Hence, the correct option is $A$ .

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