The number of moles of Cr and O in a compound are 4-8 - 1010 and 9-6 - 1010 respectively- Its empirical formula is-A- Cr 2 O 4B- Cr 3 O 6C- Cr 2 O 3D- CrO 2

The correct option is D CrO2 Molar ratio of Cr and O = 4.8 x 1010 : 9.6 x 1010 = 1 : 2 Hence, empirical formula = CrO2 ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard IX

Chemistry

Formula Mass

The number of...

Question

The number of moles of Cr and O in a compound are 4.8 x 10¹⁰ and 9.6 x 10¹⁰respectively. Its empirical formula is:

CrO₂

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Cr₂O₄

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Cr₃O₆

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Cr₂O₃

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
CrO₂

Molar ratio of Cr and O = 4.8 x 10¹⁰ : 9.6 x 10¹⁰= 1 : 2

Hence, empirical formula = CrO₂

Suggest Corrections

Similar questions

Q. The number of atoms of

C r

and

O

in a compound is

4.8 \times 10^{10}

and

9.6 \times 10^{10}

respectively. Its empirical formula is :

Q. The number of atoms of Cr and O are

4.8 \times 10^{10}

and

9.6 \times 10^{10}

respectively. Its empirical formula is?

Q. A compound contains equal masses of the element A, B and C. The atomic mass of A, B and C are 20, 40 and 60 respectively. The empirical formula of the compound is:

Q. A given sample of a pure compound contains

9.81

g of zinc,

1.8 \times 10^{23}

atoms of chromium and

0.6

mole atoms of oxygen. What is the empirical formula of the compound ?

[Atomic mass :

Z n = 65.4, C r = 52, O = 16

]

Q. Quantitative analysis of a compound shows that it contains

0.110

mole of

^{'} C^{'}

0.055

mole of

^{'} N^{'}

and

0.165

mole of

^{'} 0^{'}

. Its molecular mass is about

270

. How many atoms of carbon are there in the empirical and molecular formula of the compound respectively?

Join BYJU'S Learning Program

The number of moles of Cr and O in a compound are 4.8 x 1010 and 9.6 x 1010respectively. Its empirical formula is:

The correct option is A CrO2 Molar ratio of Cr and O = 4.8 x 1010 : 9.6 x 1010 = 1 : 2 Hence, empirical formula = CrO2

The number of moles of Cr and O in a compound are 4.8 x 10¹⁰ and 9.6 x 10¹⁰respectively. Its empirical formula is:

The correct option is A
CrO₂

Molar ratio of Cr and O = 4.8 x 10¹⁰ : 9.6 x 10¹⁰= 1 : 2

Hence, empirical formula = CrO₂