The number of moles of electrons required to reduce 0.2 mole of $C r_{2} O_{7}^{2 -} t o C r^{3 +}$

1.2

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0.6

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Solution

The correct option is A 1.2
$C r^{6 +} \to C r^{3 +}$ change is 3 moles of electrons.
1 mole of $C r_{2} O_{7}^{2 -}$ requires 6 mole of charge for reduction.
$∴$ 0.2 moles of $C r_{2} O_{7}^{2 -}$ requires 1.2 moles of charge.

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