The number of moles of $K M n O_{4}$ that will be needed to react with one mole of sulphite in an acidic solution is:

2 / 5

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3 / 5

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4 / 5

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1

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Solution

The correct option is A $2 / 5$
Reaction:

$6 H^{+} + 2 M n O_{4}^{-} + 5 S O_{3}^{2 -} \to 2 M n^{2 +} + 5 S O_{4}^{2 -} + 3 H_{2} O$

So one mole of sulphite ion will need 2/5 moles of KMnO₄

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Similar questions

K M n O_{4}

The number of moles of $K M n O_{4}$ that will be needed to react with one mole of sulphite ion in acidic solution is:

K M n O_{4}

1

S O_{3}^{2 -}

m o l e s

K M n O_{4}

o n e m o l e

M n O_{4}^{-}

S O_{3}^{2 -}

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