The number of moles of molecules present in 288 g of oxygen gas is:

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Solution

The correct option is D
9

Given mass of oxygen molecules = 288 g
The gram molecular mass of oxygen = 32 g
We know that, number of moles of oxygen molecules
= $\frac{Mass of oxygen}{Gram molecular mass}$ = $\frac{288}{32}$ = 9 moles

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The number of moles of molecules present in 288 g of oxygen gas is:

8

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