Question

The number of moles of nascent hydrogen atoms required in the reduction of one mole of $CHC{l}_3$ to $C{H}_4$ with $Zn+H_{2}O$ are:

• A. 2
• B. 3
• C. 4
• D. 6

Answer 1

The correct option is D 6

Chloroform reduces by $Zn/H_{2}O$ and 6 [H] atoms are used in this reaction.

Reaction : $CHC{l}_3+6\left[H\right]\underset{}{\overset{Zn+H_{2}O}{\to }}C{H}_4+3HCl$