The number of moles of oxygen in one litre of air containing 21% oxygen by volume under standard conditions is .

0.003

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0.006

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0.009

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0.012

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Solution

The correct option is C 0.009
$1000 m l$ of air at STP contains = $\frac{21}{100} \times 1000 = 210 m l O_{2}$

$∴$ No. of moles = $\frac{V o l . i n m l u n d e r S T P c o n d i t i o n s}{22400 m l}$

= $\frac{210}{22400} = 0.009 m o l e .$

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