The number of moles of oxygen in one litre of air containing 21% oxygen by volume under standard conditions is $^{'} X^{'}$ . What is the value of $X$ ?

0.009

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0.21

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Solution

The correct option is A 0.009
$1000 m L$ of air at STP contains $= \frac{21}{100} \times 1000 = 210 m L O_{2}$

$∴ N o . o f m o l e s = \frac{V o l . i n m L u n d e r S T P c o n d i t i o n s}{22400 m L} = \frac{210}{22400} = 0.009 m o l$
$X = 0.009$
So, $X \times 1000 = 9$

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