The number of moles of $S O_{2} C l_{2}$ in $13.5 g$ is:-

0.1

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.2

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $0.1$
Gram molecular mass of $S O_{2} C l_{2} = (32 + 2 \times 16 + 2 \times 35.5) g$
$= 135 g$
$Given mass of S O_{2} C l_{2} = 13.5 g$

$Number of gram molecules = \frac{mass}{gram molecular mass}$

$= \frac{13.5}{135}$

$= 0.1$

Suggest Corrections

Similar questions

{(\frac{0.4 \times 0.4 \times 0.4 + 0.2 \times 0.2 \times 0.2}{0.2 \times 0.2 \times 0.2 + 0.1 \times 0.1 \times 0.1})}^{3}

C l^{-}

C a C l_{2}

A + 2 B \to C + D,

(m o l e s l i t r e^{- 1})

(m o l e s l i t r e^{- 1} m i n^{- 1})

[A] [B]

0.1 0.1 6.0 \times 10^{- 3}

0.3 0.2 7.2 \times 10^{- 2}

0.3 0.4 2.88 \times 10^{- 1}

0.4 0.1 2.4 \times 10^{- 2}

The probability distribution of x is

$\begin{matrix} x & 0 & 1 & 2 & 3 P (x) & 0.2 & k & k & 2 k \end{matrix}$

Find the value of k

Join BYJU'S Learning Program