The number of moles of water present in $90$ grams of water are:

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0.5

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Solution

The correct option is D 5
The molecular weight of water is $18$ g/mol.
The number of moles in $90$ g of water is $\frac{M a s s o f w a t e r}{m o l e c u l a r w e i g h t o f w a t e r} = \frac{90 g}{18 g / m o l} = 5 m o l$

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