Question

The number of moles present in 224 L of methane (at STP) is ___

• A. 0.1
• B. 10
• C. 1
• D. 0.001

Answer 1

The correct option is B

10

Given: Volume of methane gas = 224 L
We know that, molar volume at STP (litres) = 22.4 L
In case of gases at STP,
Number of moles = $\frac{\text{Volume at STP (litres)}}{\text{Molar volume at STP (litres)}}$ .... (i)
After inserting the values of volume of methane and molar volume at STP (litres) in equation (i) we get
Number of moles of methane gas at STP in 224 L = $\frac{224}{22.4}$ = 10 mol