The number of monochlorinated products formed and the number of fractions, respectively are:

6, 5

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

6, 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5, 4

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6, 3

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 6, 5

Enantiomers bearing similar physical properties do not undergo fractional distillation they remain as a single fraction.
Diastereomers undergo fractional distillation and in the above products formed, only structure 3 is diasteromer and can be separated in two fractions.
So the total number of fractions formed are 5.

Suggest Corrections

Similar questions

P h - C | C H_{3} H - C H_{2} - C H_{3} C l_{2} - - \to h v p r o d u c t s F r a c t i o n a l - ------ \to D i s t i l l a t i o n F r a c t i o n s .

2, 3 - d i m e t h y l b u t a n e

On monochlorination of 2-methylbutane, the number of chiral compounds formed are:

Join BYJU'S Learning Program