The correct option is D 0
Comparing the terms on the RHS to that on the LHS, we get
x+1=|x−3|+4
x=|x−3|+3
If x>3
x=x−3+3 .. no solution.
And if x≤3
x=3−x+3
x=3 ...(i)
And
|x−3|+2=x−1
|x−3|=x−3
If x>3 then
x−3=x−3 no solution.
And if x≤3
3−x=x−3
x=3 ...(ii)
From i and ii, we get x=3 as one solution.
Substituting in the equation, we get
LHS =(3)2(24)+22
=9(16)+4
=148
RHS =32(24)+22
=148
Hence x=3 is one and only solution.
Hence there are no negative integral solution.