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Question

The number of negative values of a for which the inequation 4x2+2(2a+1)2x2+4a23>0 is satisfied for any x is

A
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B
0
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C
1
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D
None of these
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Solution

The correct option is A
4x2+2(2a+1)2x2+4a23>0
Put 2x2=t
t2+2(2a+1)t+4a23>0
D<0
4(2a+1)24(4a23)<0
a+1<0
a<1
a(,1)
Hence, infinite values of a are possible.

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