The number of neutrons emitted when $_{92}^{235} U$ undergoes controlled nuclear fission to $_{54}^{142} Xe$ and $_{38}^{90} Sr$ .

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Solution

The number of neutrons emitted when $_{92}^{235} U$ undergoes controlled nuclear fission to $_{54}^{142} Xe$ and $_{38}^{90} Sr$ is 4.
$_{92}^{235} U +_{0}^{1} n \to_{54}^{142} Xe +_{38}^{90} Sr + 4_{0}^{1} n + e n e r g y$

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Similar questions

Calculate the number of neutrons emitted when $_{92} U^{235}$ undergoes controlled nuclear fission to $_{54} X e^{142}$ and $_{38} S r^{90} .$

(IIT-JEE, 2010)

_{54}^{139} Xe

_{38}^{94} Sr

_{92}^{235} U

_{54}^{139} X e

_{38}^{94} S r

_{92}^{235} U

_{92}^{235} U

_{0}^{1} n

(_{56}^{144} B a +_{36}^{89} K r)

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