Question

The number of nodes for $4f$ orbital is:

• A. $0$
• B. $1$
• C. $2$
• D. $3$

Answer 1

The correct option is D $3$

For $4f$,

$n=4$ and $l=3$

Now,

Number of angular nodes $=l=3$

Number of radial nodes$=n-l-1=4-3-1=0$

$\therefore$ Total number of nodes$=3+0=3$