The number of nodes present in 3 d is-A- 2B- 1C- 0D- 3

The correct option is A 2 We know, Total number of angular nodes = l 3d ⇒ n = 3 and l = 2 Therefore, angular nodes = 2 Number of radial nodes = n l 1 = 3 ...

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Question

The number of nodes present in 3d is: _____

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Solution

The correct option is C
2

We know,
Total number of angular nodes = l
$3 d \Rightarrow n = 3 a n d l = 2$
Therefore, angular nodes = 2
Number of radial nodes = n - l - 1
= 3 - 2 - 1 = 0
$∴$ Total number of nodes = 2
Or
Total number of nodes = n - 1
= 3 - 1 = 2

Suggest Corrections

The number of nodes present in 3d is: _____

The correct option is C 2 We know, Total number of angular nodes = l 3d⇒n=3 and l=2 Therefore, angular nodes = 2 Number of radial nodes = n - l - 1 = 3 - 2 - 1 = 0 ∴ Total number of nodes = 2 Or Total number of nodes = n - 1 = 3 - 1 = 2

The correct option is C
2

We know,
Total number of angular nodes = l
$3 d \Rightarrow n = 3 a n d l = 2$
Therefore, angular nodes = 2
Number of radial nodes = n - l - 1
= 3 - 2 - 1 = 0
$∴$ Total number of nodes = 2
Or
Total number of nodes = n - 1
= 3 - 1 = 2