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Question

The number of non zero terms in the expansion of (1+32x)9+(132x)9 is

A
9
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B
0
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C
5
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D
10
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Solution

The correct option is C 5
(1+32x)9+(132x)9
Applying binomial theorem for expansion of the following
=1+(32x)(9C1)+(32x)2(9C2)...(9C9(32x)9)
+1(32x)(9C1)+(32x)2(9C2)...(9C9(32x)9)
=2[1+(32x)2(9C2)+(32x)4(9C4)...(32x)8(9C8)]
The powers of 32x are in A.P
0,2,4,6,8
Hence, including the term 1orx0 there are 9+12 terms.
Hence, there are 5 terms,

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