wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The number of non-zero terms in the expression of (1+32x)9+(132x)9 is:

A
9
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
0
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
5
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
10
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is C 5
expansion of (1+x)n
=1+nC1x+nC2x2+.......+nCnxn
(1x)n
=1nC1x+nC2x2nC3x2+........
Adding,
(1+x)n+(1x)n=2(1+nC2x2+nC4x4+......)
(1+32x)9+(132x)9
=2(1+9C2(32x)2+9C4(32x)4+9C6(32x)6+9C8(32x)8)
So, there are 5 non-zero terms in the expression.

1182382_1292951_ans_861ddf8455d14e2293be0d6eb26b8069.jpg

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Visualising the Terms
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon