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Question

The number of nonzero terms in the expansion of (x+a)100+(x−a)100 is

A
100
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B
51
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C
201
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D
202
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Solution

The correct option is D 51
(x+a)100+(xa)100
=100C0x100+100C1x99a+100C2x98a2+....+100C100xoa100+100C0x100100C1x99a+100C2x98a2...+100C100x0a100

Here all the odd powers of 'a' get cancelled.

The terms with ao,a2,a4,...a100 will be present.
There are 51 terms.

i.e., 2k where k=0,1,2,......50
a
Hence the given expression has 51 terms.

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