Question

The number of numbers greater than a million that can be formed with the digits 2, 3, 0, 3, 4, 2 and 3 is :

• A. 360
• B. 340
• C. 370
• D. 350

Answer 1

The correct option is A 360

Here $one$ $million$ $=1000000$,

Given no;s. are $2,3,0,3,4,2,3$

A number greater than $1000000$ has $7$ places,and all digits are to be used.

But $2$ repeated twice and $3$ repeated thrice .

$\therefore$ Total no. of ways arranging $7$ digits$=\frac{7!}{213!}=420$

But, the no. begins with $0$ are no more $7$ digits no. then reject those no.'s.

These can be arranged in $\frac{6!}{2!3!}=60$

$\therefore$Required no. of arrangements. $420-60=360$