The number of numbers lying between 10 and 1000 that can be formed with 0, 2, 3, 4, 5, 6 so that no digit being repeated in any number is

100

No worries! We‘ve got your back. Try BYJU‘S free classes today!

125

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

120

No worries! We‘ve got your back. Try BYJU‘S free classes today!

240

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 125
Two digits number (0 can't come on unit place)

$5 \times 5 = 25$
Three digits number

$5 \times 5 \times 4 = 100$
Hence total number of numbers between 10 and 1000 that can be formed using given digits is $= 125$

Suggest Corrections

Similar questions

1, 2, 4, 5, 6, 7

5

3000

4000

3, 4, 5, 6, 7

8

The number of numbers lying between 99 and 1000 which can be formed using the digits 2, 3, 7, 0, 6, 8 when no digit is being repeated is

400

1000

0, 2, 3, 4, 5, 6,

Join BYJU'S Learning Program