The correct option is C 36
For a number to be divisible by 4, the last 2 digits must be divisible by 4 (divisibility rule of 4)
So, the combinations of the last 2 digits of above numbers(1,2,3,5,6) that are divisible by are
12,32,52,16,36,56
and the first 2 digits are to be selected from the remaining 3 digits(the digits other than the ones n last 2 digits) and this can be done in 3P2=6 ways
From above, there are six such cases with different last 2 digits
So, the total number of numbers=6×6=36