Question

The number of octahedral void(s) per atom present in a face - centered cubic unit cell is:
[1 mark]

• A. $1$
• B. $3$
• C. $2$
• D. $4$

Answer 1

The correct option is A $1$

The number of atoms present in a face - centered cubic unit cell i s $4$
So number of tetrahedral voids = $2\times 4=8$
Number of octahedral voids = $4$
So, the number of octahedral void(s) per atom present in a face - centered cubic unit cell is $=\frac{4}{4}=1$