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Reductions Involving Aldehydes or Ketones

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Question

The number of $- O H$ groups in product of above compound is ____.

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Solution

$2 - O H$ groups are present in product.
In this reaction, reduction of ketonic group takes place.

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Q. How is Carbonyl group converted into above compound?

- | C | O H - | C | O H -

How many number of -OH group in the product?

H O O C - C H (O H) - C H (O H) - C H (O H) - C O O H

What is the number of optically inactive isomers in the given above compound?

Q. How many functional group are present in above compound?

C H_{3} - O - C | | O - C | O H H - C H = C H - C - O | | C - O H

The number of enantiomeric pairs that can be grouped from the products formed by the monochlorination of the compound given above is .

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Reductions Involving Aldehydes or Ketones

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