The number of optically active isomers in the compound $C H_{3} C H (O H) C O O H$ is:

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Solution

The correct option is A 2

Optically active isomers $= 2^{1}$
$= 2$

Option B is correct.

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Similar questions

{C H}_{3} C H B r C H B r C O O H

The total number of optically active isomers for $C H_{2} O H (C H O H)_{3} C H O$ are:

{C H}_{2} O H {(C H O H)}_{3} C H O

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