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Spin Quantum Number

The number of...

Question

The number of orbitals with $n = 5, m_{l} = + 2$ is . (Round off to the nearest integer).

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Solution

For $n = 5 l = 0, 1, 2, 3, 4$
$l = 2 \to m = - 2, - 1, 0, + 1, + 2$
$l = 3 \to m = - 3, - 2, - 1, 0, + 1, + 2, + 3$
$l = 4 \to m = - 4, - 3, - 2, - 1, 0, + 1, + 2, + 3, + 4$
Total no. of orbitals $= 3$ .

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