Question

The number of ordered pair (a,x) satisfying the equation $se{c}^2$(a + 2)x + $a^2$ - 1 = 0; -$\pi$ < x < $\pi$ is

• A. 2
• B. 1
• C. 3
• D. Infinite

Answer 1

The correct option is C

3

$ta{n}^2$(a + 2)x + $a^2$ = 0

⇒ $ta{n}^2$(a + 2)x = 0 and a = 0

$ta{n}^2$ 2x = 0 ⇒ x = 0, $\frac{\pi }{2}$, $\frac{-\pi }{2}$

∴ (0, 0), (0, $\frac{\pi }{2}$), (0, $\frac{-\pi }{2}$) are the ordered pairs