The number of ordered pairs (α,β), where α,β∈(−π,π) satisfying cos(α−β)=1 and cos(α+β)=1e is
A
0
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B
1
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C
2
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D
4
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Solution
The correct option is D4 Given, (α,β)ϵ(−π,π), and cos(α−β)=1 −2π<α−β<2π,α−β=2nπ So α−β=0,α=β Now, cos(α+β)=1e⇒cos2α=1e So, there are four sets - two in [0.2π) & two is (−2π,0] So option D is the correct answer