CameraIcon
CameraIcon
SearchIcon
MyQuestionIcon
MyQuestionIcon
Question

The number of ordered triplets of natural numbers (a,b,c) for which abc11 is

A
52
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
53
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
55
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
56
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D 56
abc=1 in 1 way

Consider abc=2
This can be done by the permutation of 1,1,2 which can be done in 3!2!=3 ways
So, abc=2,3,5,7,11 in 3×5=15 ways
Similarly, abc=4,9 in 6×2=12 ways
abc=6,10 in 9×2=18 ways
abc=8 in 1+6+3=10 ways
So, total number =56

flag
Suggest Corrections
thumbs-up
0
BNAT
mid-banner-image