Question

The number of oxygen atoms in $4.4$ gm of $C{O}_2$ is :

• A. $1.2\times {10}^{23}$ atoms
• B. $6\times {10}^{22}$ atoms
• C. $6\times {10}^{23}$ atoms
• D. $12\times {10}^{23}$ atoms

Answer 1

The correct option is A $1.2\times {10}^{23}$ atoms

Moles of $C{O}_2=\frac{4.4}{44}=0.1mole$

Number of oxygen atoms$=2\times molesofC{O}_2\times N_A=0.2N_A=1.2\times {10}^{23}atoms$