Question

The number of oxygen atoms in $4.4\text{g}$ of $C{O}_2$ is:

• A. $1.2\times {10}^{23}$
• B. $6\times {10}^{23}$
• C. $6\times {10}^{22}$
• D. $12\times {10}^{23}$

Answer 1

The correct option is A $1.2\times {10}^{23}$

$1\text{mol of}C{O}_2=44\text{g of}C{O}_2$
$\therefore 4.4\text{g}C{O}_2=0.1\text{mol}C{O}_2=6\times {10}^{22}\text{molecules}$
Since, $1\text{mol}C{O}_2=6\times {10}^{23}\text{molecules}$
$2\times 6\times {10}^{22}\text{atoms of O}=1.2\times {10}^{23}\text{atoms of O}$