The number of oxygen atoms present in 1 mole of oxalic acid dihydrate is:

6 \times 10^{23}

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6.022 \times 10^{34}

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7.22 \times 10^{23}

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36.13 \times 10^{23}

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Solution

The correct option is D $36.13 \times 10^{23}$
Oxalic acid dihydrate is $C_{2} H_{2} O_{4} .2 H_{2} O$

One molecule of Oxalic acid dihydrate contains 6 oxygen atoms

1 mol of Oxalic acid dihydrate contains $6 \times N_{A}$ atoms of oxygen

i.e. $6 \times 6.022 \times 10^{23} = 36.13 \times 10^{23}$ atoms

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Similar questions

One mole of any substance contains $6.022 \times 10^{23}$ atoms/molecules. Number of molecules of $H_{2} S O_{4}$ present in 100 mL of $0.02 M H_{2} S O_{4}$ solution is.............

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Q. Find the number of moles of oxygen atoms present in

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6.022 \times 10^{23}

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(a) $6.022 \times 10^{23}$ molecules of oxygen

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are:

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The number of oxygen atoms present in 1 mole of oxalic acid dihydrate is:

The correct option is D 36.13×1023Oxalic acid dihydrate is C2H2O4.2H2OOne molecule of Oxalic acid dihydrate contains 6 oxygen atoms1 mol of Oxalic acid dihydrate contains 6×NA atoms of oxygeni.e. 6×6.022×1023=36.13×1023 atoms