Question

The number of oxygen atoms present in $14.6g$ of magnesium bicarbonate $\left[Mg\right(HCO3\left)2\right]$ is

• A. $6N_A$
• B. $0.6N_A$
• C. $N_A$
• D. $0.5N_A$

Answer 1

Answer: (B)

$0.6N_A$

weight of magnesium bicarbonate = 14.6 g

molecular mass of magnesium bicarbonate = 146 g

no. of moles = $\frac{14.6}{146}$ = 0.1

in 1 mole of magnesium bicarbonate moles of oxygen atom = 6

in 0.1 moles of magnesium bicarbonate moles of oxygen atom = 0.6 mole

so, no. ofoxygen atom present = 0.6 $N_A$