Question

The number of $p\pi -d\pi$ bonds present in monomeric $S{O}_3$ is :

Answer 1

$S$ in $S{O}_3$ is $s{p}^2$ hybridized. Three $\sigma$ bonds are formed between the three $s{p}^2$ hybridised orbital of sulphur and 3 pure $p$ orbitals of three oxygen atoms.

We have one pure $p$ orbital and two pure $d$ orbitals in sulphur. These 3 orbitals are involved in one $p\pi -p\pi$ bond and two $p\pi -d\pi$ bonds.